x^2+10x+50+122-3X=180

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Solution for x^2+10x+50+122-3X=180 equation:



x^2+10x+50+122-3x=180
We move all terms to the left:
x^2+10x+50+122-3x-(180)=0
We add all the numbers together, and all the variables
x^2+7x-8=0
a = 1; b = 7; c = -8;
Δ = b2-4ac
Δ = 72-4·1·(-8)
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-9}{2*1}=\frac{-16}{2} =-8 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+9}{2*1}=\frac{2}{2} =1 $

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